A number is selected at random from first 30 natural numbers. What is the probability that the number is a multiple of either 3 or 13?
(A) 17/30
(B) 2/5
(C) 7/15
(D) 4/15
(E) 11/30
Answer -- B
The first 30 natural nos are 1,2,3.....28,29,30.
There are 10 multiples of 3 in the above range and there are 2 multiples of 13 in the same range.
Hence there are total 12 i.e (10+2) nos which can be either a multiple of 3 or 13.
Total numbers = 30.
So the probability is 12/30 = 2/5.