If x is not equal to zero, is 1/x > 1 ?

1) y/ x > y

2) x^3 > x^2

Answer: B

From statement (1): y/x > y

=> y > xy

=> y(1-x) > 0

y>0 when x is less than 1 or y<0 when x is greater than 1 ---- hence insufficient

From statement (2): x^3 > x^2

=> x^2(x-1) > 0

=> x^2 >0 and x>1

Since x>1, 1/x can not be greater than 1 ---- hence sufficient

Hence B

1) y/ x > y

2) x^3 > x^2

Answer: B

From statement (1): y/x > y

=> y > xy

=> y(1-x) > 0

y>0 when x is less than 1 or y<0 when x is greater than 1 ---- hence insufficient

From statement (2): x^3 > x^2

=> x^2(x-1) > 0

=> x^2 >0 and x>1

Since x>1, 1/x can not be greater than 1 ---- hence sufficient

Hence B