Wednesday, August 30, 2006

Manhattan Challenge Problem of the week ! - Aug 28

High Functioning

The vertical position of an object can be approximated at any given time by the function: p(t) = rt – 5t2 + b where p(t) is the vertical position in meters, t is the time in seconds, and r and b are constants. After 2 seconds, the position of an object is 41 meters, and after 5 seconds the position is 26 meters. What is the position of the object, in meters, after 4 seconds?

(A) 24

(B) 26

(C) 39

(D) 41

(E) 45

Answer - D , for OE click on link below.
Manhattan challenge problem