Manhattan challenge problem of the week !

A is the sum of x consecutive positive integers. b is the sum of y consecutive positive integers. For which of the following values of x and y is it impossible that a = b?

(A) x = 2; y = 6

(B) x = 3; y = 6

(C) x = 7; y = 9

(D) x = 10; y = 4

(E) x = 10; y = 7

Answer - D

Since the sum of 10 consecutive positive integers is always odd and 4 consecutive positive integers is always even, there sum a and b will never be equal, thus by above logic D is the answer.